Figure 2.24 The graphs of f(x) and g(x) are identical for all x ≠ 1. Their limits at 1 are equal. We see that. lim x → 1x2 − 1 x − 1 = lim x → 1 ( x − 1) ( x + 1) x − 1 = lim x → 1(x + 1) = 2. The limit has the form lim x → a f ( x) g ( x), where lim x → af(x) = 0 and lim x → ag(x) = 0. Algebra. Graph f (x)=|x|. f (x) = |x| f ( x) = | x |. Find the absolute value vertex. In this case, the vertex for y = |x| y = | x | is (0,0) ( 0, 0). Tap for more steps... (0,0) ( 0, 0) The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression ...Rule 3: Additive identity I don't know if you interpreted the definition of the vector addition of your vector space correctly, but your reasoning for Rule 3 seems to be a bit odd. f (x)+g(x)= f (x) f (g(x))= f (x) ... Since you already know that h is a continuous bijection, you need only show that h is an open map, i.e., that h[U] is open in h ...Proof verification: if f,g: [a,b] → R are continuous and f = g a.e. then f = g. Your proof goes wrong here "The non-empty open sets in [a,b] are one of these forms: [a,x), (x,b], (x,y) or [a,b] itself..." That statement about open sets is just wrong. For instance, the union of ... 3) g(x)= f (x)−(mx+b)= f (x)−xf (1)+(x−1)f (0).Solving for (f ∘ g )(x) watch fully. College Algebra getting to you? No worries I got you covered check out my other videos for help. If you don't see what ...The challenge problem says, "The graphs of the equations y=f(x) and y=g(x) are shown in the grid below." So basically the two graphs is a visual representation of what the two different functions would look like if graphed and they're asking us to find (f∘g)(8), which is combining the two functions and inputting 8. The resulting function is known as a composite function. We represent this combination by the following notation: (f ∘ g)(x) = f(g(x)) We read the left-hand side as “f composed with g at x ,” and the right-hand side as “f of g of x. ” The two sides of the equation have the same mathematical meaning and are equal. Apr 24, 2017 · In order to find what value (x) makes f (x) undefined, we must set the denominator equal to 0, and then solve for x. f (x)=3/ (x-2); we set the denominator,which is x-2, to 0. (x-2=0, which is x=2). When we set the denominator of g (x) equal to 0, we get x=0. So x cannot be equal to 2 or 0. Please click on the image for a better understanding. Rule 3: Additive identity I don't know if you interpreted the definition of the vector addition of your vector space correctly, but your reasoning for Rule 3 seems to be a bit odd. f (x)+g(x)= f (x) f (g(x))= f (x) ... Since you already know that h is a continuous bijection, you need only show that h is an open map, i.e., that h[U] is open in h ... Arithmetic Combinations of Functions. The sum, difference, product, or quotient of functions can be found easily. (f / g) (x) = f (x) / g (x), as long as g (x) isn't zero. The domain of each of these combinations is the intersection of the domain of f and the domain of g. In other words, both functions must be defined at a point for the ...Functions f and g are inverses if f(g(x))=x=g(f(x)). For every pair of such functions, the derivatives f' and g' have a special relationship. Learn about this relationship and see how it applies to 𝑒ˣ and ln(x) (which are inverse functions!).What you called \times is called function composition, and is written (g ∘ f)(x) = g(f(x)). As you noted, it's not commutative, but it is associative. Whenever the compositions are defined, (h ∘ g) ∘ f = h ∘ (g ∘ f) = h ∘ g ∘ f. In a way, the function iteration can be extended to fractional exponents as well. Bachelors. Here we asked to compute G composed with G of X, which means take the function G of X, plug it in for X in itself, so what we'll do is take two X plus 7 and plug that in for X in the function two X plus 7. So out comes the X in goes the two X plus 7. And there we will use parentheses appropriately because it is multiplication.f( ) = 3( ) + 4 (10) f(g(x)) = 3(g(x)) + 4 (11) f(x2 + 1 x) = 3(x2 + 1 x) + 4 (12) f(x 2+ 1 x) = 3x + 3 x + 4 (13) Thus, (f g)(x) = f(g(x)) = 3x2 + 3 x + 4. Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but with one extra step. Find (f g h)(x) given f, g, and h below. f(x) = 2x (14) g(x) = x2 + 2x ...A very quick tutorial for how to evaluate a simple composite function. f(g(x)) Step 1: Identify the functions f and g you will do function composition for. Step 2: Clearly establish the internal and external function. In this case we assume f is the external function and g is the internal formula. Step 3: The composite function is defined as (f g) (x) = f (g (x)) You can simplify the resulting output of f (g (x)), and in ... Suppose we have functions f and g, where each function is defined by a set of (x, y) points. To do the composition g(f(x))), we follow these steps: Choose a point in the set for f. Take the x -value of that point as the input into f. The output of f is the y -value from that same point.Video transcript. - So we have the graphs of two functions here. We have the graph y equals f of x and we have the graph y is equal to g of x. And what I wanna do in this video is evaluate what g of, f of, let me do the f of it another color, f of negative five is, f of negative five is. And it can sometimes seem a little daunting when you see ...Function composition (or composition of functions) usually looks like f (g (x) ) or (f ∘ g ) (x), which both read as "f of g of x." To help us better understand function composition , let’s imagine we want to buy some merch, and we can use two coupons to bring down the original price . Given two functions, add them, multiply them, subtract them, or divide them (on paper). I have another video where I show how this looks using only the grap...Suppose we have functions f and g, where each function is defined by a set of (x, y) points. To do the composition g(f(x))), we follow these steps: Choose a point in the set for f. Take the x -value of that point as the input into f. The output of f is the y -value from that same point.Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. See full list on mathsisfun.com Example: f (x)=√x and g (x)=√ (3−x) The domain for f (x)=√x is from 0 onwards: The domain for g (x)=√ (3−x) is up to and including 3: So the new domain (after adding or whatever) is from 0 to 3: If we choose any other value, then one or the other part of the new function won't work. In other words we want to find where the two ...Jul 7, 2022 · The function f(g(x)) represents the amount that Sonia will earn per hour by baking bread. What is a Function? A function assigns the value of each element of one set to the other specific element of another set. Given f(x)=9x²+1 and g(x)=√(2x³). Therefore, the value of f(g(x)) will be, = 9(2x³) + 1 = 18x³ + 1 There are rules we can follow to find many derivatives. For example: The slope of a constant value (like 3) is always 0. The slope of a line like 2x is 2, or 3x is 3 etc. and so on. Here are useful rules to help you work out the derivatives of many functions (with examples below ). Note: the little mark ’ means derivative of, and f and g are ...You have f(x) =x2 + 1 f ( x) = x 2 + 1 and g(f(x)) = 1/(x2 + 4) g ( f ( x)) = 1 / ( x 2 + 4). Now pause and think about the second function. The function is defined as g(f(x)) g ( f ( x)), right. now what if there is some way that you could manipulate this function and some how change it to g(x) g ( x).Learn how to find the formula of the inverse function of a given function. For example, find the inverse of f (x)=3x+2. Inverse functions, in the most general sense, are functions that "reverse" each other. For example, if f f takes a a to b b, then the inverse, f^ {-1} f −1, must take b b to a a. Or in other words, f (a)=b \iff f^ {-1} (b)=a ...A composite function is a function that depends on another function. A composite function is created when one function is substituted into another function. For example, f (g (x)) is the composite function that is formed when g (x) is substituted for x in f (x). f (g (x)) is read as “f of g of x ”. f (g (x)) can also be written as (f ∘ g ...Share a link to this widget: More. Embed this widget ». Added Aug 1, 2010 by ihsankhairir in Mathematics. To obtain the composite function fg (x) from known functions f (x) and g (x). Use the hatch symbol # as the variable when inputting. Send feedback | Visit Wolfram|Alpha. Use this calculator to obtain the composite function fg (x)More formally, given and g: X → Y, we have f = g if and only if f(x) = g(x) for all x ∈ X. [6] [note 2] The domain and codomain are not always explicitly given when a function is defined, and, without some (possibly difficult) computation, one might only know that the domain is contained in a larger set.Generally, an arithmetic combination of two functions f and g at any x that is in the domain of both f and g, with one exception. The quotient f/g is not defined at values of x where g is equal to 0. For example, if f (x) = 2x + 1 and g (x) = x - 3, then the doamins of f+g, f-g, and f*g are all real numbers. The domain of f/g is the set of all ...In practice, there is not much difference between evaluating a function at a formula or expression, and composing two functions. There's a notational difference, of course, but evaluating f (x) at y 2, on the one hand, and composing f (x) with g(x) = y 2, on the other hand, have you doing the exact same steps and getting the exact same answer ...The composite functions of higher math often use h(x) and g(x), in combination,,defining which comes first, and which is second. The substitution is bad enough, but using y's would make it worse.. In summary, feel free to immediately use "y =" instead of "h(x)", if it clarified the problem.Mar 30, 2017 · Learn how to solve f(g(x)) by replacing the x found in the outside function f(x) by g(x). Share a link to this widget: More. Embed this widget ». Added Aug 1, 2010 by ihsankhairir in Mathematics. To obtain the composite function fg (x) from known functions f (x) and g (x). Use the hatch symbol # as the variable when inputting. Send feedback | Visit Wolfram|Alpha. Use this calculator to obtain the composite function fg (x) Proof verification: if f,g: [a,b] → R are continuous and f = g a.e. then f = g. Your proof goes wrong here "The non-empty open sets in [a,b] are one of these forms: [a,x), (x,b], (x,y) or [a,b] itself..." That statement about open sets is just wrong. For instance, the union of ... 3) g(x)= f (x)−(mx+b)= f (x)−xf (1)+(x−1)f (0).There are rules we can follow to find many derivatives. For example: The slope of a constant value (like 3) is always 0. The slope of a line like 2x is 2, or 3x is 3 etc. and so on. Here are useful rules to help you work out the derivatives of many functions (with examples below ). Note: the little mark ’ means derivative of, and f and g are ...Rule 3: Additive identity I don't know if you interpreted the definition of the vector addition of your vector space correctly, but your reasoning for Rule 3 seems to be a bit odd. f (x)+g(x)= f (x) f (g(x))= f (x) ... Since you already know that h is a continuous bijection, you need only show that h is an open map, i.e., that h[U] is open in h ... The resulting function is known as a composite function. We represent this combination by the following notation: (f ∘ g)(x) = f(g(x)) We read the left-hand side as “f composed with g at x ,” and the right-hand side as “f of g of x. ” The two sides of the equation have the same mathematical meaning and are equal. Step 1: Identify the functions f and g you will do function composition for. Step 2: Clearly establish the internal and external function. In this case we assume f is the external function and g is the internal formula. Step 3: The composite function is defined as (f g) (x) = f (g (x)) You can simplify the resulting output of f (g (x)), and in ... (f+g)(x) is shorthand notation for f(x)+g(x). So (f+g)(x) means that you add the functions f and g (f-g)(x) simply means f(x)-g(x). So in this case, you subtract the functions. (f*g)(x)=f(x)*g(x). So this time you are multiplying the functions and finally, (f/g)(x)=f(x)/g(x). Now you are dividing the functions.Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. Learn how to solve f(g(x)) by replacing the x found in the outside function f(x) by g(x).f( ) = 3( ) + 4 (10) f(g(x)) = 3(g(x)) + 4 (11) f(x2 + 1 x) = 3(x2 + 1 x) + 4 (12) f(x 2+ 1 x) = 3x + 3 x + 4 (13) Thus, (f g)(x) = f(g(x)) = 3x2 + 3 x + 4. Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but with one extra step. Find (f g h)(x) given f, g, and h below. f(x) = 2x (14) g(x) = x2 + 2x ... It's a big theorem that all rational functions have elementary antiderivatives. The general way to integrate a rational function is to factor it into quadratics and linears (this is always possible by FTA), and use partial fractions decomposition. For our specific example, we have to factor x4 −x2 + 1 x 4 − x 2 + 1.First write the composition in any form like (gof)(x)asg(f (x))or(gof)(x2)asg(f (x2)) ( g o f) ( x) a s g ( f ( x)) o r ( g o f) ( x 2) a s g ( f ( x 2)). Put the value of x in the outer function with the inside function then just simplify the function. Although, you can manually determine composite functions by following these steps but to ... Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.Which expression is equivalent to (f + g) (4)? f (4) + g (4) If f (x) = 3 - 2x and g (x)=1/x+5, what is the value of (f/9) (8)? -169. If f (x) = x2 - 2x and g (x) = 6x + 4, for which value of x does (f + g) (x) = 0? -2. The graphs of f (x) and g (x) are shown below.Which expression is equivalent to (f + g) (4)? f (4) + g (4) If f (x) = 3 - 2x and g (x)=1/x+5, what is the value of (f/9) (8)? -169. If f (x) = x2 - 2x and g (x) = 6x + 4, for which value of x does (f + g) (x) = 0? -2. The graphs of f (x) and g (x) are shown below. gf(x) = g(f(x)) = g(x2) = x2 +3. Here is another example of composition of functions. This time let f be the function given by f(x) = 2x and let g be the function given by g(x) = ex. As before, we write down f(x) first, and then apply g to the whole of f(x). In this case, f(x) is just 2x. Applying the function g then raises e to the power f(x ...(f+g)(x) is shorthand notation for f(x)+g(x). So (f+g)(x) means that you add the functions f and g (f-g)(x) simply means f(x)-g(x). So in this case, you subtract the functions. (f*g)(x)=f(x)*g(x). So this time you are multiplying the functions and finally, (f/g)(x)=f(x)/g(x). Now you are dividing the functions. gf(x) = g(f(x)) = g(x2) = x2 +3. Here is another example of composition of functions. This time let f be the function given by f(x) = 2x and let g be the function given by g(x) = ex. As before, we write down f(x) first, and then apply g to the whole of f(x). In this case, f(x) is just 2x. Applying the function g then raises e to the power f(x ...Chart drawing f (x),g (x) [1-5] /5. Disp-Num. [1] 2017/07/11 19:54 60 years old level or over / A teacher / A researcher / Useful /. Purpose of use. For 21 August 2017 Sun''s eclipse observations of General Relativity effects on directions of stars near the darkened Sun. Comment/Request. Given that f(x)=9-x^2 and g(x)=5x^2+2x+1, Sal finds (f+g)(x). Created by Sal Khan and Monterey Institute for Technology and Education.Rule 3: Additive identity I don't know if you interpreted the definition of the vector addition of your vector space correctly, but your reasoning for Rule 3 seems to be a bit odd. f (x)+g(x)= f (x) f (g(x))= f (x) ... Since you already know that h is a continuous bijection, you need only show that h is an open map, i.e., that h[U] is open in h ...Through a worked example involving f (x)=√ (x²-1) and g (x)=x/ (1+x), learn about function composition: the process of combining two functions to create a new function. This involves replacing the input of one function with the output of another function.It's a big theorem that all rational functions have elementary antiderivatives. The general way to integrate a rational function is to factor it into quadratics and linears (this is always possible by FTA), and use partial fractions decomposition. For our specific example, we have to factor x4 −x2 + 1 x 4 − x 2 + 1.It's a big theorem that all rational functions have elementary antiderivatives. The general way to integrate a rational function is to factor it into quadratics and linears (this is always possible by FTA), and use partial fractions decomposition. For our specific example, we have to factor x4 −x2 + 1 x 4 − x 2 + 1.Generally, an arithmetic combination of two functions f and g at any x that is in the domain of both f and g, with one exception. The quotient f/g is not defined at values of x where g is equal to 0. For example, if f (x) = 2x + 1 and g (x) = x - 3, then the doamins of f+g, f-g, and f*g are all real numbers. The domain of f/g is the set of all ... What does (f ∘ g) mean in math? - Quora. Something went wrong. Wait a moment and try again.Arithmetic operations on a function calculator swiftly finding the value of the arithmetic multiplication operation. Example 4: f (x)=2x+4. g (x)= x+1. (f÷g) (x)=f (x)÷g (x) (f÷g) (x)= (2x+4)÷(x+1) The quotient of two functions calculator is especially designed to find the quotient value when dividing the algebraic functions. Remember that the value of f' (x) anywhere is just the slope of the tangent line to f (x). On the graph of a line, the slope is a constant. The tangent line is just the line itself. So f' would just be a horizontal line. For instance, if f (x) = 5x + 1, then the slope is just 5 everywhere, so f' (x) = 5. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.The domain means all the possible values of x and the range means all the possible values of y. The functions are given below. f (x) = x. g (x) = 1. Then the domain of the function (g/f) (x) will be. (g/f) (x) = 1 / x. Then the graph of the function is given below. The domain of the function is a real number except 0 because the function is not ...Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.Operations on Functions. Functions with overlapping domains can be added, subtracted, multiplied and divided. If f(x) and g(x) are two functions, then for all x in the domain of both functions the sum, difference, product and quotient are defined as follows. (f + g)(x) = f(x) + g(x) (f − g)(x) = f(x) − g(x) (fg)(x) = f(x) × g(x) (f g)(x ... Algebra. Find the Domain (fg) (x) (f g) (x) ( f g) ( x) The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. Interval Notation: (−∞,∞) ( - ∞, ∞) Set -Builder Notation: {x|x ∈ R} { x | x ∈ ℝ }Algebra. Graph f (x)=|x|. f (x) = |x| f ( x) = | x |. Find the absolute value vertex. In this case, the vertex for y = |x| y = | x | is (0,0) ( 0, 0). Tap for more steps... (0,0) ( 0, 0) The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression ...What does (f ∘ g) mean in math? - Quora. Something went wrong. Wait a moment and try again.F of G of X. To find f (g (x)), we just substitute x = g (x) in the function f (x). For example, when f (x) = x and g (x) = 3x - 5, then f (g (x)) = f (3x - 5) = (3x - 5) g (f (x)) = a function obtained by replacing x with f (x) in g (x). For example, if f (x) = x and g (x) = sin x, then (i) f (g (x)) = f (sin x) = (sin x) x whereas (ii) g (f ...Free functions composition calculator - solve functions compositions step-by-step Apr 30, 2011. #2. the letter which you use to label a function has no special meaning. g (x) just identifies a function of x, in the same way as that f (x) does. Using a "g" instead of an "f" only means the function has a different label assigned to it. Typically this is done where you have already got an f (x), so creating another one would be ...Proof verification: if f,g: [a,b] → R are continuous and f = g a.e. then f = g. Your proof goes wrong here "The non-empty open sets in [a,b] are one of these forms: [a,x), (x,b], (x,y) or [a,b] itself..." That statement about open sets is just wrong. For instance, the union of ... 3) g(x)= f (x)−(mx+b)= f (x)−xf (1)+(x−1)f (0).AboutTranscript. Functions assign outputs to inputs. The domain of a function is the set of all possible inputs for the function. For example, the domain of f (x)=x² is all real numbers, and the domain of g (x)=1/x is all real numbers except for x=0. We can also define special functions whose domains are more limited.(f+g)(x) is shorthand notation for f(x)+g(x). So (f+g)(x) means that you add the functions f and g (f-g)(x) simply means f(x)-g(x). So in this case, you subtract the functions. (f*g)(x)=f(x)*g(x). So this time you are multiplying the functions and finally, (f/g)(x)=f(x)/g(x). Now you are dividing the functions. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. What you called \times is called function composition, and is written (g ∘ f)(x) = g(f(x)). As you noted, it's not commutative, but it is associative. Whenever the compositions are defined, (h ∘ g) ∘ f = h ∘ (g ∘ f) = h ∘ g ∘ f. In a way, the function iteration can be extended to fractional exponents as well. Composite functions and Evaluating functions : f(x), g(x), fog(x), gof(x) Calculator - 1. f(x)=2x+1, g(x)=x+5, Find fog(x) 2. fog(x)=(x+2)/(3x), f(x)=x-2, Find gof(x ...(f+g)(x) is shorthand notation for f(x)+g(x). So (f+g)(x) means that you add the functions f and g (f-g)(x) simply means f(x)-g(x). So in this case, you subtract the functions. (f*g)(x)=f(x)*g(x). So this time you are multiplying the functions and finally, (f/g)(x)=f(x)/g(x). Now you are dividing the functions.
Apr 29, 2017 · Besides being called (composition) commutative, it is sometimes also said that such functions are permutable, e.g. see here.As an example, a classic result of Ritt shows that permutable polynomials are, up to a linear homeomorphism, either both powers of x, both iterates of the same polynomial, or both Chebychev polynomials. . Malin akerman nuda
Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals. For math, science, nutrition, history ...Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. Oct 29, 2007 · Bachelors. Here we asked to compute G composed with G of X, which means take the function G of X, plug it in for X in itself, so what we'll do is take two X plus 7 and plug that in for X in the function two X plus 7. So out comes the X in goes the two X plus 7. And there we will use parentheses appropriately because it is multiplication. gf(x) = g(f(x)) = g(x2) = x2 +3. Here is another example of composition of functions. This time let f be the function given by f(x) = 2x and let g be the function given by g(x) = ex. As before, we write down f(x) first, and then apply g to the whole of f(x). In this case, f(x) is just 2x. Applying the function g then raises e to the power f(x ...Rule 3: Additive identity I don't know if you interpreted the definition of the vector addition of your vector space correctly, but your reasoning for Rule 3 seems to be a bit odd. f (x)+g(x)= f (x) f (g(x))= f (x) ... Since you already know that h is a continuous bijection, you need only show that h is an open map, i.e., that h[U] is open in h ... A composite function is a function that depends on another function. A composite function is created when one function is substituted into another function. For example, f (g (x)) is the composite function that is formed when g (x) is substituted for x in f (x). f (g (x)) is read as “f of g of x ”. f (g (x)) can also be written as (f ∘ g ...Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Trigonometry. Find f (g (x)) f (x)=3x-4 , g (x)=x+2. f (x) = 3x − 4 f ( x) = 3 x - 4 , g(x) = x + 2 g ( x) = x + 2. Set up the composite result function. f (g(x)) f ( g ( x)) Evaluate f (x+ 2) f ( x + 2) by substituting in the value of g g into f f. f (x+2) = 3(x+2)−4 f ( x + 2) = 3 ( x + 2) - 4. Simplify each term.Step 1: Identify the functions f and g you will do function composition for. Step 2: Clearly establish the internal and external function. In this case we assume f is the external function and g is the internal formula. Step 3: The composite function is defined as (f g) (x) = f (g (x)) You can simplify the resulting output of f (g (x)), and in ...Free functions composition calculator - solve functions compositions step-by-stepA very quick tutorial for how to evaluate a simple composite function. f(g(x))Nov 17, 2017 · The domain means all the possible values of x and the range means all the possible values of y. The functions are given below. f (x) = x. g (x) = 1. Then the domain of the function (g/f) (x) will be. (g/f) (x) = 1 / x. Then the graph of the function is given below. The domain of the function is a real number except 0 because the function is not ... Example: f (x)=√x and g (x)=√ (3−x) The domain for f (x)=√x is from 0 onwards: The domain for g (x)=√ (3−x) is up to and including 3: So the new domain (after adding or whatever) is from 0 to 3: If we choose any other value, then one or the other part of the new function won't work. In other words we want to find where the two ...See full list on mathsisfun.com Graphically, for any function f(x), the statement that f(a)=b means that the graph of f(x) passes through the point (a,b). If you look at the graphs of f(x) and g(x), you will see that the graph of f(x) passes through the point (3,6) and the graph of g(x) passes though the point (3,3). This is why f(3)=6 and g(3)=3. .